NumberFormatException

Hi!

Folgende Methode

public MessageInfo(String msg) throws Exception {
		String[] fields = msg.split(";");
		if (fields.length!=2)
			throw new Exception("MessageInfo: Invalid string for message construction: " + msg);
		System.out.println(msg);
		System.out.println(fields[0]);
		System.out.println(fields[1]);
		totalMessages = Integer.parseInt(fields[0]);
		System.out.println(totalMessages);
		messageNum = Integer.parseInt(fields[1]);
		System.out.println("not anymore2");
	}

Dazu der Output:

10;1

10
1

10
java.lang.NumberFormatException: For input string: "1
"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:456)
at java.lang.Integer.parseInt(Integer.java:497)
at common.MessageInfo.<init>(MessageInfo.java:38)
at udp.UDPServer.processMessage(UDPServer.java:81)
at udp.UDPServer.run(UDPServer.java:63)
at udp.UDPServer.main(UDPServer.java:151)
Exception in thread "main" java.lang.NullPointerException
at udp.UDPServer.processMessage(UDPServer.java:88)
at udp.UDPServer.run(UDPServer.java:63)
at udp.UDPServer.main(UDPServer.java:151)

Aus irgendeinem Grund will der den 2. String nicht richtig parsen

Hat jemand eine Ahnung warum?

Tzugi

^^da ist ein zeilenumbruch drin, der muss erstmal wech. geht mit String.trim()

Integer.parseInt() might throw NumberFormatExceptions if characters other than digits and ';' are in the string. You should place them in try-blocks. Try something like this:

public MessageInfo(String msg) throws Exception {
int totalMessages=0, messageNum=0;
String[] fields = msg.split(";");
if (fields.length!=2)
throw new Exception("MessageInfo: Invalid string for message
construction: " + msg);
System.out.println(msg);
System.out.println(fields[0]);
System.out.println(fields[1]);
try{
totalMessages = Integer.parseInt(fields[0]);
}catch(NumberFormatException nfe){
System.out.println("Substring 1 contains non-digit characters!
Parsing...");
totalMessages = parseInt(fields[0]);
System.out.println("Debug: "+totalMessages);
}
System.out.println(totalMessages);
try{
messageNum = Integer.parseInt(fields[1]);
}catch(NumberFormatException nfe){
System.out.println("Substring 2 contains non-digit characters!
Parsing...");
messageNum = parseInt(fields[1]);
System.out.println("Debug: "+messageNum);
}
System.out.println("not anymore2");
}

public int parseInt(String str)
{
if(str==null){
System.out.println("String to be parsed is null! Returning 0.");
return 0;
}
int count=0, x=0;
char[] string = str.toCharArray();
for(int i=str.length()-1; i>=0; i--){
if(Character.isDigit(string[i]) && count>=0){
x+=Character.getNumericValue(string[i])*Math.pow(10,count++);
}else if(!Character.isDigit(string[i]) && count>0){
count=-1;
}else if(Character.isDigit(string[i]) && count<0){
System.out.println("More than one Int in Substring!! Returning
leftmost only.");
return x;
}
}
if(count==0)
System.out.println("No integer found! Returning 0.");
return x;
}

x4u

System.out.println(fields[1].trim());

tut's auch. Das entfernt dir alle Leerzeichen vor und nach der Zahl im String, falls da welche sind.