Extremwert

[MrBesserwisser]

\left|{{x}\choose{4-x^2}} - {{0}\choose{0}}\right| = \left|{x}\choose{4-x^2}\right| = \sqrt{x^2 + (4-x)^2} = \mbox{min}
\Rightarrow x^2 + (4-x)^2 = \mbox{min}
$\Rightarrow 2x - 2(4-x) = 0$
$\Rightarrow 4x = 8$
$\Rightarrow x = 2$
$\Rightarrow y = 4 -2^2 = 0$