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Seien a,b > 0 natürliche Zahlen, sodass (ab + 1) | (a² + b²). Warum ist dann (a² + b²)/(ab + 1) eine Quadratzahl?
http://math.stackexchange.com/questions/28438/alternative-proof-that-a2b2-ab1-is-a-square-when-its-an-integer
Cheatz0r :p
:p