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Warum ist Hom(A,B)⊗Z_p=Hom_G(T_pA,T_pB)Hom(A,B)\otimes\mathbf{Z}\_p = Hom\_G(T\_pA,T\_pB)Hom(A,B)⊗Z_p=Hom_G(T_pA,T_pB)?